The integral shows a floor function multiplied by a fractional function. Evaluate the integral.
Solution
To start off, we should note that any real number is composed of its integer and its fractional part
For example, 3.5 = 3 + 0.5
With this, we will rewrite the fractional function as
Substituting this into our integral gives us
We will now limit the integral to the interval (n, n+1), this transforms the integral into the follows
Using the reverse power rule, we arrive at
Upon simplifying, we arrive at
As the integral ranges from x = 0 to x = 20, it’s equivalent to finding
The upper limit is 19 because, in the interval (19, 20), the floor function takes any value in the interval as 19
Computing the summation, we get
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